Q40.For a d4 metal ion in an octahedral field, the correct electronic configuration is : (1) t3 2g e1g when ΔO < P (2) t32g e1g when ΔO > P (3) t42g e0g when ΔO < P (4) e2g t22g when ΔO < P
What This Question Tests
This question tests the understanding of Crystal Field Theory (CFT) and how d-electrons are filled in an octahedral complex depending on the relative magnitude of pairing energy and crystal field splitting energy for a d⁴ metal ion.
Concepts Tested
📚 NCERT Sections This Tests
5.18 — What Is Crystal Field Splitting Energy? How Does The Magnitude Of Do Decide
Chemistry Class 11 · Chapter 5
5.18 What is crystal field splitting energy? How does the magnitude of Do decide the actual configuration of d orbitals in a coordination entity?
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.25 — Explain The Violet Colour Of The Complex [Ti(H2O)6] 3+ On The Basis Of Crystal
Chemistry Class 11 · Chapter 5
5.25 Explain the violet colour of the complex [Ti(H2O)6] 3+ on the basis of crystal field theory.
📋 Question Details
- Chapter
- Coordination Compounds
- Topic
- Crystal Field Theory (CFT)
- Year
- 2020
- Shift
- 06 Sep Shift 2
- Q Number
- Q40
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 9: Coordination Compounds
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