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PhysicsMediumNumerical2020 · 05 Sep Shift 2

Q25.The surface of a metal is illuminated alternately with photons of energies E1 = 4 eV and E2 = 2. 5 eV respectively. The ratio of maximum speeds of the photoelectrons emitted in the two cases is 2. The work function of the metal in (eV) is..........

What This Question Tests

This problem combines the photoelectric equation with the kinetic energy formula to determine the work function of a metal given the incident photon energies and the ratio of maximum photoelectron speeds.

Concepts Tested

Einstein's photoelectric equationWork functionMaximum kinetic energyMaximum speed of photoelectrons

Formulas Used

KE_max = E - Φ

KE_max = (1/2)mv_max²

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