Q58.For hydrogen like species, which of the following graphs provides the most appropriate representation of E vs Z plot for a constant n ? [E: Energy of the stationary state, Z : atomic number, n = principal quantum number] (1) (2) (3) (4)
What This Question Tests
This question requires identifying the correct graph representing the relationship between the energy of a stationary state (E) and the atomic number (Z) for a hydrogen-like species at a constant principal quantum number (n).
Concepts Tested
Formulas Used
E_n = -13.6 Z²/n² eV
📚 NCERT Sections This Tests
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Energy of hydrogen-like species
- Year
- 2025
- Shift
- 29 Jan Shift 2
- Q Number
- Q58
- Type
- Graph based
- NCERT Ref
- Class 11 Chemistry Ch 2: Structure of Atom
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