Q38.Which one of the following pairs of species have the same bond order? (1) CN− and NO+ (2) CN− and CN+ (3) O−2 and CN− (4) NO+ and CN+
What This Question Tests
This question requires calculating the bond order for different diatomic species. CN⁻ has (6+7)+1 = 14 electrons, giving a bond order of 3. NO⁺ has (7+8)-1 = 14 electrons, also giving a bond order of 3. Thus, CN⁻ and NO⁺ have the same bond order.
Concepts Tested
Formulas Used
Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2
📚 NCERT Sections This Tests
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.19 — [Cr(Nh3)6] 3+ Is Paramagnetic While [Ni(Cn)4] 2– Is Diamagnetic. Explain Why?
Chemistry Class 11 · Chapter 5
5.19 [Cr(NH3)6] 3+ is paramagnetic while [Ni(CN)4] 2– is diamagnetic. Explain why? 5.20 A solution of [Ni(H2O)6] 2+ is green but a solution of [Ni(CN)4] 2– is colourless. Explain. 5.21 [Fe(CN)6] 4– and [Fe(H2O)6] 2+ are of different colours in dilute solutions. Why?
📋 Question Details
- Chapter
- Chemical Bonding
- Topic
- Bond Order, Molecular Orbital Theory
- Year
- 2008
- Shift
- Unknown
- Q Number
- Q38
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 4: Chemical Bonding and Molecular Structure
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