Q10.Water is flowing through a horizontal tube having cross-sectional areas of its two ends being A and A′ such that the ratio A/A′ is 5 . If the pressure difference of water between the two ends is 3× 105 N m−2 , the velocity of water with which it enters the tube will be (neglect gravity effects) (1) 5 m s−1 (2) 10 m s−1 (3) 25 m s−1 (4) 50√10 m s−1
What This Question Tests
This problem requires the application of both the equation of continuity and Bernoulli's principle to find the velocity of water given the cross-sectional areas and pressure difference.
Concepts Tested
Formulas Used
A₁v₁ = A₂v₂
P₁ + 1/2 ρv₁² = P₂ + 1/2 ρv₂²
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📋 Question Details
- Chapter
- Properties of Matter
- Topic
- Fluid dynamics (Bernoulli's equation and continuity)
- Year
- 2012
- Shift
- 12 May Online
- Q Number
- Q10
- Type
- MCQ
- NCERT Ref
- Class 11 Physics Ch 10: Mechanical Properties of Fluids
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