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PhysicsMediumMCQ2006 · Unknown

Q22.A whistle producing sound waves of frequencies 9500 Hz and above is approaching a stationary person with speed v ms−1 . The velocity of sound in air is 300 ms−1 . If the person can hear frequencies upto a maximum of 10, 000 Hz, the maximum value of v upto which he can hear the whistle is (1) 30 ms−1 (2) 15√2 ms−1 (3) 15/√2 ms−1 (4) 15 ms−1

What This Question Tests

This question applies the Doppler effect formula for a source approaching a stationary observer to find the maximum speed of the source for a specific frequency range to be audible.

Concepts Tested

Doppler Effect in SoundApparent FrequencySource Approaching Observer

Formulas Used

f' = f₀ * (v_sound / (v_sound - v_source))

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