Q76.The area (in sq. unit) bounded by the curve 4y2 = x2(4 −x)(x −2) is equal to (1) π8 (2) 3π8 (3) 3π (4) π 2 16 0 < x < 2. 1 , with
What This Question Tests
This question requires calculating the area bounded by a given curve, which involves rewriting the equation and performing definite integration, possibly recognizing standard integral forms.
Concepts Tested
Formulas Used
Area = ∫ y dx
Area = ∫ sqrt(x^2(4-x)(x-2))/2 dx
📚 NCERT Sections This Tests
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2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
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13.2 Obtain the binding energy of the nuclei 5626Fe and 20983 Bi in units of MeV from the following data: m ( 5626Fe ) = 55.934939 u m ( 20983 Bi ) = 208.980388 u
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2.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere (c) at a point 18 cm from the centre of the sphere?
📋 Question Details
- Chapter
- Definite Integration & Area
- Topic
- Area Bounded by Curves
- Year
- 2021
- Shift
- 18 Mar Shift 2
- Q Number
- Q76
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 8: Application of Integrals
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