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MathsMediumMCQ2020 · 03 Sep Shift 1

Q67.The solution curve of the differential equation, (1 + e−x)(1 + y2) dxdy = y2 which passes through the point (0, 1), is + 2 ) + 2) (1) y2 + 1 = y(loge( 1+e−x2 ) 2) (2) y2 + 1 = y(loge( 1+ex (3) y2 = 1 + y loge( 1+ex2 ) (4) y2 = 1 + y loge( 1+e−x2 )

What This Question Tests

This question tests the ability to solve a first-order differential equation by separating variables and then applying the given initial condition to find the particular solution.

Concepts Tested

Separation of variablesIntegrationInitial value problems

Formulas Used

∫ (1/y^2) dy

∫ (1/(1+e^(-x))) dx = ∫ (e^x/(e^x+1)) dx

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📋 Question Details

Chapter
Differential Equations
Topic
Solution of variable separable differential equations
Year
2020
Shift
03 Sep Shift 1
Q Number
Q67
Type
MCQ
NCERT Ref
Class 12 Mathematics Ch 9: Differential Equations

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