Q54. pH value of 0. 001 MNaOH solution is
What This Question Tests
Tests the ability to calculate the pH of a strong base solution using its concentration and the relationship between pH and pOH.
Concepts Tested
Formulas Used
pOH = -log[OH-]
pH + pOH = 14
📚 NCERT Sections This Tests
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
1.1 — Define The Term Solution. How Many Types Of Solutions Are Formed? Write Briefly
Chemistry Class 11 · Chapter 1
1.1 Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.
2.8 — The Conductivity Of 0.20 M Solution Of Kcl At 298 K Is 0.0248 S Cm–1. Calculate
Chemistry Class 11 · Chapter 2
2.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.
📋 Question Details
- Chapter
- Ionic Equilibrium
- Topic
- pH of strong base solution
- Year
- 2022
- Shift
- 27 Jun Shift 2
- Q Number
- Q54
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 7: Ionic Equilibrium
More from this Chapter
Q95.Species acting as both Bronsted acid and base is (1) (HSO4)−1 (2) Na2CO3 (3) NH3 (4) OH−1
Q96.Let the solubility of an aqueous solution of Mg(OH)2 be x then its ksp is (1) 4x3 (2) 108x5 (3) 27x4 (4) 9x
Q97.The solubility of Mg(OH)2 is S moles/litre. The solubility product under the same condition is (1) 4 S3 (2) 3S 4 (3) 4 S2 (4) S 3
Q98.How do we differentiate between Fe3+ and Cr3+ in group III? (1) by taking excess of NH4OH solution (2) by increasing NH4+ ion concentration (3) by decreasing OH− ion concentration (4) both (b) and (c)