Q66.If the 7th term in the binomial expansion of 9 , x > 0 , is equal to 729 , then x can be: + √3 ln x) ( 3√843 (1) e2 (2) e (3) e (4) 2e 2
What This Question Tests
This question involves finding a specific term in a binomial expansion, setting it equal to a given value, and solving the resulting logarithmic equation for x. The term `3√8` is interpreted as `(8)^(1/3) = 2` due to typical JEE context for OCR errors.
Concepts Tested
Formulas Used
T_(r+1) = C(n,r) * a^(n-r) * b^r
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📋 Question Details
- Chapter
- Binomial Theorem
- Topic
- General term of binomial expansion
- Year
- 2013
- Shift
- 22 Apr Online
- Q Number
- Q66
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 8: Binomial Theorem
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