Q66.If the number of terms in the expansion of (1 −2x + y24 ) of all the terms in this expansion is (1) 243 (2) 729 (3) 64 (4) 2187
What This Question Tests
This question tests the fundamental properties of trinomial expansions, specifically how to determine the number of terms and the sum of coefficients by substitution.
Concepts Tested
Formulas Used
Number of terms in (a+b+c)^n = (n+1)(n+2)/2
Sum of coefficients = P(1,1,1)
📚 NCERT Sections This Tests
5.12 — Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 · Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
1.1 — Define The Term Solution. How Many Types Of Solutions Are Formed? Write Briefly
Chemistry Class 11 · Chapter 1
1.1 Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
📋 Question Details
- Chapter
- Binomial Theorem
- Topic
- Trinomial expansion properties
- Year
- 2016
- Shift
- 03 Apr
- Q Number
- Q66
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 8: Binomial Theorem
More from this Chapter
Q89.In the binomial expansion of (a −b)n, n ≥5 , the sum of 5th and 6th terms is zero, then ab equals (1) 5 (2) 6 n−4 n−5 (3) n−5 (4) n−4 6 5
Q90.The sum of the series 20C0 −20C1 + 20C2 −20C3 + … −… + 20C10 is (1) −20C10 (2) 12 20C10 (3) 0 (4) 20C10
Q77.Statement-1: ∑nr=0(r + 1)nCr = (n + 2)2n−1 Statement -2: ∑nr=0(r + 1)nCrxr = (1 + x)n + nx(1 + x)n−1 . JEE Main 2008 JEE Main Previous Year Paper (1) Statement −1 is false, Statement −2 is true (2) Statement −1 is true, Statement −2 is true, Statement −2 is a correct explanation for Statement −1 (3) Statement −1 is true, Statement −2 is true; (4) Statement −1 is true, Statement −2 is false. Statement −2 is not a correct explanation for Statement −1.
Q65.The remainder left out when 82n −(62)2n+1 is divided by 9 is (1) 0 (2) 2 (3) 7 (4) 8