Q25.A tuning fork is vibrating at 250 Hz. The length of the shortest closed organ pipe that will resonate with the tuning fork will be _____ cm. (Take speed of sound in air as 340 m s−1 )
What This Question Tests
This question tests the fundamental concept of resonance in a closed organ pipe, requiring the calculation of the shortest length for resonance given the speed of sound and the tuning fork frequency.
Concepts Tested
Formulas Used
v = fλ
λ = 4L (for fundamental mode in closed organ pipe)
📚 NCERT Sections This Tests
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📋 Question Details
- Chapter
- Waves & Sound
- Topic
- Resonance in organ pipes
- Year
- 2021
- Shift
- 27 Aug Shift 2
- Q Number
- Q25
- Type
- Numerical
- NCERT Ref
- Class 11 Physics Ch 15: Waves
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