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PhysicsMediumMCQ2016 · 03 Apr

Q23.Radiation of wavelength λ is incident on a photocell. The fastest emitted photoelectron has a speed v . If the 3λ wavelength is changed to , the speed of the fastest emitted photoelectron will be 4 4 2 (1) = v( 1 1 3 ) 2 (2) = v( 34 ) 2 (3) > v( 3 1 1 4 ) 2 (4) < v( 43 )

What This Question Tests

The question applies Einstein's photoelectric equation to relate the wavelength of incident radiation, work function, and the maximum kinetic energy (and thus speed) of emitted photoelectrons for two different wavelengths.

Concepts Tested

Photoelectric effect equationEnergy of a photonKinetic energy of photoelectron

Formulas Used

E = hc/λ

KE_max = E - Φ

KE_max = ½mv²

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