Q80.Let A be a set of all 4 -digit natural numbers whose exactly one digit is 7. Then the probability that a randomly chosen element of A leaves remainder 2 when divided by 5 is: (1) 1 (2) 122 5 297 (3) 97 (4) 2 297 9
What This Question Tests
This question requires careful counting of 4-digit numbers with exactly one digit as 7, then identifying those that leave a remainder of 2 when divided by 5, to calculate the probability.
Concepts Tested
Formulas Used
P(E) = n(E) / n(S)
Permutations/Combinations for forming numbers
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📋 Question Details
- Chapter
- Probability
- Topic
- Counting and probability
- Year
- 2021
- Shift
- 25 Feb Shift 2
- Q Number
- Q80
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 13: Probability
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