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PhysicsMediumMCQ2019 · 11 Jan Shift 2

Q21.A particle of mass m and charge q is in an electric and magnetic field given by → → E = 2^i + 3^j; B = 4^j + 6^k The charged particle is shifted from the origin to the point P(x = 1; y = 1) along a straight path. The magnitude of the total work done is : (1) (0.35)q (2) 5q (3) (2.5) q (4) (0.15)q

What This Question Tests

This question assesses the understanding that a magnetic field does no work on a charged particle, and calculates the work done solely by the electric field when a charge moves along a given path.

Concepts Tested

Work-energy theoremWork done by electric fieldWork done by magnetic field

Formulas Used

W = ∫F.dr

W_E = q(V_i - V_f)

F_E = qE

W_B = 0

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