Q10.A 10 μF capacitor is fully charged to a potential difference of 50 V After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V . The capacitance of the second capacitor is : (1) 15 μF (2) 30 μF (3) 20 μF (4) 10 μF
What This Question Tests
This question tests the principle of conservation of charge when a charged capacitor is connected in parallel with an uncharged capacitor, requiring calculation of the capacitance of the second capacitor.
Concepts Tested
Formulas Used
Q = CV
C_eq = C₁ + C₂
📚 NCERT Sections This Tests
2.7 — Three Capacitors Of Capacitances 2 Pf, 3 Pf And 4 Pf Are Connected
Physics Class 11 · Chapter 2
2.7 Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. (a) What is the total capacitance of the combination? (b) Determine the charge on each capacitor if the combination is connected to a 100 V supply.
2.6 — Three Capacitors Each Of Capacitance 9 Pf Are Connected In Series.
Physics Class 11 · Chapter 2
2.6 Three capacitors each of capacitance 9 pF are connected in series. (a) What is the total capacitance of the combination? (b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
2.5 — A Parallel Plate Capacitor With Air Between The Plates Has A
Physics Class 11 · Chapter 2
2.5 A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10–12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
📋 Question Details
- Chapter
- Electrostatics
- Topic
- Capacitors in Parallel
- Year
- 2020
- Shift
- 02 Sep Shift 2
- Q Number
- Q10
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 2: Electrostatic Potential and Capacitance
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