Q35.The difference between ∆H and ∆U is ∆H - ∆U, when the combustion of one mole of heptane l is carried out at a temperature T , is equal to: (1) -4RT (2) 3RT (3) 4RT (4) -3RT
What This Question Tests
This question requires writing a balanced combustion reaction, calculating the change in the number of moles of gaseous species (Δn_g), and applying the relationship between ΔH and ΔU.
Concepts Tested
Formulas Used
ΔH = ΔU + Δn_g RT
Balancing chemical equations
📚 NCERT Sections This Tests
3.23 — The Rate Constant For The Decomposition Of Hydrocarbons Is 2.418 × 10–5S–1
Chemistry Class 11 · Chapter 3
3.23 The rate constant for the decomposition of hydrocarbons is 2.418 × 10–5s–1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.
3.20 — For The Decomposition Of Azoisopropane To Hexane And Nitrogen At 543
Chemistry Class 11 · Chapter 3
3.20 For the decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data are obtained. t (sec) P(mm of Hg) 0 35.0 360 54.0 720 63.0 Calculate the rate constant.
1.35 — Henry’S Law Constant For The Molality Of Methane In Benzene At 298 K Is
Chemistry Class 11 · Chapter 1
1.35 Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.
📋 Question Details
- Chapter
- Thermodynamics & Thermochemistry
- Topic
- Relation between ΔH and ΔU
- Year
- 2019
- Shift
- 10 Apr Shift 2
- Q Number
- Q35
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 6: Thermodynamics
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