Q6. The pressure acting on a submarine is 3 × 105 Pa at a certain depth. If the depth is doubled, the percentage increase in the pressure acting on the submarine would be: (Assume that atmospheric pressure is 1 × 105 Pa density of water is 103 kg m−3, g = 10 ms−2 ) (1) 200 3 % (2) 2005 % (3) 200 5 % (4) 2003 %
What This Question Tests
This problem involves calculating the initial depth from the given pressure and then determining the new pressure when the depth is doubled, finally finding the percentage increase in pressure.
Concepts Tested
Formulas Used
P = P_atm + ρgh
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1.36 100 g of liquid A (molar mass 140 g mol–1) was dissolved in 1000 g of liquid B (molar mass 180 g mol–1). The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr. 29 Solutions Reprint 2025-26
📋 Question Details
- Chapter
- Properties of Matter
- Topic
- Pressure in fluids, Pascal's law
- Year
- 2021
- Shift
- 16 Mar Shift 1
- Q Number
- Q6
- Type
- MCQ
- NCERT Ref
- Class 11 Physics Ch 10: Mechanical Properties of Fluids
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