Q51.When 35 mL of 0. 15 M lead nitrate solution is mixed with 20 mL of 0. 12 M chromic sulphate solution, ____________ ×10−5 moles of lead sulphate precipitate out. (Round off to the Nearest Integer).
What This Question Tests
This question involves calculating the moles of precipitate formed in a reaction by identifying the limiting reagent using given molarities and volumes of reactants.
Concepts Tested
Formulas Used
moles = Molarity × Volume
Stoichiometric ratios
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📋 Question Details
- Chapter
- Solutions
- Topic
- Stoichiometry of Precipitation Reactions
- Year
- 2021
- Shift
- 16 Mar Shift 2
- Q Number
- Q51
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 1: Some Basic Concepts of Chemistry
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