Q55.The molarity of the solution prepared by dissolving 6. 3 g of oxalic acid (H2C2O4 ⋅2H2O) in 250 mL of water in mol L−1 is x × 10−2. The value of x is _________ . (Nearest integer) [Atomic mass : H : 1. 0, C : 12. 0, 0 : 16. 0 J]
What This Question Tests
This question involves a straightforward calculation of molarity given the mass of solute (hydrated oxalic acid) and the volume of the solution.
Concepts Tested
Formulas Used
Molarity = moles of solute / volume of solution (L)
Molar mass of H2C2O4.2H2O = 126 g/mol
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📋 Question Details
- Chapter
- Solutions
- Topic
- Molarity calculation
- Year
- 2021
- Shift
- 31 Aug Shift 1
- Q Number
- Q55
- Type
- Numerical
- NCERT Ref
- Class 12 Chemistry Ch 2: Solutions
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