Q63.If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is equal to (1) 7 (2) 4 (3) 5 (4) 6
What This Question Tests
This question requires applying the formula for the sum of a geometric progression and adapting it to find the sum of terms at odd positions, then solving for the common ratio.
Concepts Tested
Formulas Used
Sn = a(r^n - 1)/(r - 1)
📚 NCERT Sections This Tests
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5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
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12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
📋 Question Details
- Chapter
- Sequences & Series
- Topic
- Geometric Progression (GP)
- Year
- 2024
- Shift
- 29 Jan Shift 1
- Q Number
- Q63
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 9: Sequences and Series
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