Q24.Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes 0. 01 cm3 of oleic acid per cm3 of the solution. Then you make a thin film of this solution (monomolecular thickness) of 1 area 4 cm2 by considering 100 spherical drops of radius ( 40π3 ) 3 × 10−3 cm. Then the thickness of oleic acid layer will be x × 10−14 m . Where x is ________ .
What This Question Tests
This question tests the experimental method of determining molecular size using the volume of oleic acid solution, the number of drops, and the area of the monomolecular film.
Concepts Tested
Formulas Used
V_sphere = (4/3)πr³
V_film = Area × thickness
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📋 Question Details
- Chapter
- Properties of Matter
- Topic
- Measurement of molecular size (oleic acid experiment)
- Year
- 2021
- Shift
- 17 Mar Shift 2
- Q Number
- Q24
- Type
- Numerical
- NCERT Ref
- Class 11 Physics Ch 2: Units and Measurements
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