Q55.A solution containing 2 g of a non-volatile solute in 20 g of water boils at 373 . 52 K. The molecular mass of the solute is _____ gmol-1. (Nearest integer) Given, water boils at 373 K, Kb for water = 0 . 52K kg mol-1
What This Question Tests
This question requires calculating the number of moles of CO2 from its molarity and volume, then converting moles to volume at STP using the given molar volume.
Concepts Tested
Formulas Used
n = Molarity * Volume (L)
V = n * Molar Volume at STP
📚 NCERT Sections This Tests
1.34 — Vapour Pressure Of Water At 293 K Is 17.535 Mm Hg. Calculate The Vapour
Chemistry Class 11 · Chapter 1
1.34 Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.
1.36 — 100 G Of Liquid A (Molar Mass 140 G Mol–1) Was Dissolved In 1000 G Of Liquid B
Chemistry Class 11 · Chapter 1
1.36 100 g of liquid A (molar mass 140 g mol–1) was dissolved in 1000 g of liquid B (molar mass 180 g mol–1). The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr. 29 Solutions Reprint 2025-26
2.8 — The Conductivity Of 0.20 M Solution Of Kcl At 298 K Is 0.0248 S Cm–1. Calculate
Chemistry Class 11 · Chapter 2
2.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.
📋 Question Details
- Chapter
- States of Matter
- Topic
- Ideal gas law
- Year
- 2023
- Shift
- 30 Jan Shift 1
- Q Number
- Q55
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 5: States of Matter
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