Q18.Visible light of wavelength 6000 × 10−8cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at 60o from the central maximum. If the first minimum is produced at θ1, then θ1 is close to (1) 20o (2) 30o (3) 25o (4) 45o
What This Question Tests
This question tests the application of the single-slit diffraction condition for minima to find the slit width using the second minimum and then determine the angle for the first minimum.
Concepts Tested
Formulas Used
a sinθ = nλ
📚 NCERT Sections This Tests
10.4 — In A Young’S Double-Slit Experiment, The Slits Are Separated By
Physics Class 12 · Chapter 10
10.4 In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.
10.5 — In Young’S Double-Slit Experiment Using Monochromatic Light Of
Physics Class 12 · Chapter 10
10.5 In Young’s double-slit experiment using monochromatic light of wavelength l, the intensity of light at a point on the screen where path difference is l, is K units. What is the intensity of light at a point where path difference is l/3?
9.4 — Figures 9.27(A) And (B) Show Refraction Of A Ray In Air Incident At 60°
Physics Class 12 · Chapter 9
9.4 Figures 9.27(a) and (b) show refraction of a ray in air incident at 60° with the normal to a glass-air and water-air interface, respectively. Predict the angle of refraction in glass when the angle of incidence in water is 45° with the normal to a water-glass interface [Fig. 9.27(c)]. FIGURE 9.27
📋 Question Details
- Chapter
- Wave Optics
- Topic
- Single Slit Diffraction
- Year
- 2020
- Shift
- 07 Jan Shift 1
- Q Number
- Q18
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 10: Wave Optics
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