Q52.In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively: (1) sp3d, trigonal bipyramidal (2) d2sp3 , octahedral (3) dsp2 , square planar (4) sp3 , tetrahedral
What This Question Tests
This question tests knowledge of Wilkinson's catalyst, [RhCl(PPh₃)₃]. Rhodium is in a +1 oxidation state with a d⁸ configuration, forming a square planar complex with dsp² hybridization.
Concepts Tested
📚 NCERT Sections This Tests
5.23 — Give The Oxidation State, D Orbital Occupation And Coordination Number Of
Chemistry Class 11 · Chapter 5
5.23 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes: (i) K3[Co(C2O4)3] (iii) (NH4)2[CoF4] (ii) cis-[CrCl2(en)2]Cl (iv) [Mn(H2O)6]SO4
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
📋 Question Details
- Chapter
- Coordination Compounds
- Topic
- VBT in Coordination Compounds, Wilkinson's Catalyst
- Year
- 2018
- Shift
- 16 Apr Online
- Q Number
- Q52
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 9: Coordination Compounds
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