Q4. The position vector of a particle related to time t is given by →r= (10tˆi + 15t2ˆj + 7ˆk)m . The direction of net force experienced by the particle is : (1) Positive x-axis (2) In x −y plane (3) Positive y-axis (4) Positive z-axis
What This Question Tests
This question requires calculating the acceleration vector by differentiating the position vector twice and then determining the direction of force using Newton's second law.
Concepts Tested
Formulas Used
v = dr/dt
a = dv/dt
F = ma
📚 NCERT Sections This Tests
4.4 — A Horizontal Overhead Power Line Carries A Current Of 90 A In East To
Physics Class 11 · Chapter 4
4.4 A horizontal overhead power line carries a current of 90 A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5 m below the line?
4.6 — A 3.0 Cm Wire Carrying A Current Of 10 A Is Placed Inside A Solenoid
Physics Class 11 · Chapter 4
4.6 A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
1.15 — What Is The Net Flux Of The Uniform Electric Field Of Exercise 1.14
Physics Class 11 · Chapter 1
1.15 What is the net flux of the uniform electric field of Exercise 1.14 through a cube of side 20 cm oriented so that its faces are parallel to the coordinate planes?
📋 Question Details
- Chapter
- Laws of Motion
- Topic
- Force and Acceleration
- Year
- 2023
- Shift
- 15 Apr Shift 1
- Q Number
- Q4
- Type
- MCQ
- NCERT Ref
- Class 11 Physics Ch 4: Motion in a Plane; Ch 5: Laws of Motion
More from this Chapter
Q1. Two forces are such that the sum of their magnitudes is 18 N and their resultant is 12 N which is perpendicular to the smaller force. Then the magnitudes of the forces are (1) 12 N, 6 N (2) 13 N, 5 N (3) 10 N, 8 N (4) 16 N, 2 N
Q6. The minimum velocity (in ms−1 ) with which a car driver must traverse a flat curve of radius 150 m and coefficient of friction 0.6 to avoid skidding is (1) 60 (2) 30 (3) 15 (4) 25
Q7. A lift is moving down with acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively (1) g, g (2) g - a, g - a (3) g - a, g (4) a, g
Q8. When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed then the acceleration of the particle is (1) F1/m (2) F2 F3/mF1 (3) (F2 −F3)/m (4) F2/m