Q63.For the natural numbers m, n, if (1 −y)m(1 + y)n = 1 + a1y + a2y2 + … . +am+nym+n and a1 = a2 = 10, then the value of m + n, is equal to: (1) 88 (2) 64 (3) 100 (4) 80
What This Question Tests
The question asks to find the sum m+n given coefficients a1 and a2 from the product of two binomial expansions. It requires calculating the coefficients of y and y^2 from the product of (1-y)^m and (1+y)^n and solving the resulting system of equations.
Concepts Tested
Formulas Used
(1+x)^n = Σ C(n,k)x^k
(1-x)^m = Σ C(m,k)(-x)^k
📚 NCERT Sections This Tests
13.5 — The Q Value Of A Nuclear Reaction A + B ® C + D Is Defined By
Physics Class 12 · Chapter 13
13.5 The Q value of a nuclear reaction A + b ® C + d is defined by Q = [ mA + mb – mC – md]c2 where the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic. (i) 11 H+13 H →12 H+12 H (ii) 126 C+126 C →1020 Ne+ 24 He Atomic masses are given to be m ( 12 H ) = 2.014102 u m ( 13 H) = 3.016049 u m ( 126 C ) = 12.000000 u m ( 1020 Ne ) = 19.992439 u
5.28 — How Many Ions Are Produced From The Complex Co(Nh3)6Cl2 In Solution?
Chemistry Class 11 · Chapter 5
5.28 How many ions are produced from the complex Co(NH3)6Cl2 in solution? (i) 6 (ii) 4 (iii) 3 (iv) 2 139 Coordination Compounds Reprint 2025-26
13.2 — Obtain The Binding Energy Of The Nuclei 5626Fe And 20983 Bi In Units Of
Physics Class 12 · Chapter 13
13.2 Obtain the binding energy of the nuclei 5626Fe and 20983 Bi in units of MeV from the following data: m ( 5626Fe ) = 55.934939 u m ( 20983 Bi ) = 208.980388 u
📋 Question Details
- Chapter
- Binomial Theorem
- Topic
- Expansion of binomial expressions
- Year
- 2021
- Shift
- 20 Jul Shift 2
- Q Number
- Q63
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 8: Binomial Theorem
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