Q64.Given a sequence of 4 numbers, first three of which are in G.P. and the last three are in A.P. with common difference six. If first and last terms of this sequence are equal, then the last term is : (1) 16 (2) 8 (3) 4 (4) 2
What This Question Tests
This question tests the understanding of properties of both Geometric Progression and Arithmetic Progression and the ability to set up and solve equations based on given conditions.
Concepts Tested
Formulas Used
b^2 = ac (for GP)
common difference (d) for AP
a_n = a + (n-1)d
๐ NCERT Sections This Tests
8.2 โ Name The Following Compounds According To Iupac System Of Nomenclature:
Chemistry Class 12 ยท Chapter 8
8.2 Name the following compounds according to IUPAC system of nomenclature: (i) CH3CH(CH3)CH2CH2CHO (ii) CH3CH2COCH(C2H5)CH2CH2Cl (iii) CH3CH=CHCHO (iv) CH3COCH2COCH3 (v) CH3CH(CH3)CH2C(CH3)2COCH3 (vi) (CH3)3CCH2COOH (vii) OHCC6H4CHO-p
2.1 โ Two Charges 5 ร 10โ8 C And โ3 ร 10โ8 C Are Located 16 Cm Apart. At
Physics Class 11 ยท Chapter 2
2.1 Two charges 5 ร 10โ8 C and โ3 ร 10โ8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
1.3 โ Define The Following Terms:
Chemistry Class 11 ยท Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
๐ Question Details
- Chapter
- Sequences & Series
- Topic
- Arithmetic Progression, Geometric Progression
- Year
- 2013
- Shift
- 25 Apr Online
- Q Number
- Q64
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 9: Sequences and Series
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