Q13.An electron with energy 0. 1 keV moves at right angle to the earth's magnetic field of 1 × 10−4 Wbm−2 . The frequency of revolution of the electron will be (Take mass of electron = 9. 0 × 10−31 kg) (1) 1. 6 × 105 Hz (2) 5. 6 × 105 Hz (3) 2. 8 × 106 Hz (4) 1. 8 × 106 Hz
What This Question Tests
This question tests the understanding of a charged particle's motion in a uniform magnetic field, specifically calculating the cyclotron frequency given its kinetic energy and the magnetic field strength.
Concepts Tested
Formulas Used
KE = 1/2 mv^2
f = qB / (2πm)
📚 NCERT Sections This Tests
4.11 — In A Chamber, A Uniform Magnetic Field Of 6.5 G (1 G = 10–4 T) Is
Physics Class 11 · Chapter 4
4.11 In a chamber, a uniform magnetic field of 6.5 G (1 G = 10–4 T) is maintained. An electron is shot into the field with a speed of 4.8 × 106 m s–1 normal to the field. Explain why the path of the electron is a circle. Determine the radius of the circular orbit. (e = 1.5 × 10–19 C, me = 9.1×10–31 kg)
4.12 — In Exercise 4.11 Obtain The Frequency Of Revolution Of The Electron In
Physics Class 11 · Chapter 4
4.12 In Exercise 4.11 obtain the frequency of revolution of the electron in its circular orbit. Does the answer depend on the speed of the electron? Explain.
4.4 — A Horizontal Overhead Power Line Carries A Current Of 90 A In East To
Physics Class 11 · Chapter 4
4.4 A horizontal overhead power line carries a current of 90 A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5 m below the line?
📋 Question Details
- Chapter
- Magnetic Effects of Current
- Topic
- Motion of Charged Particle in Magnetic Field
- Year
- 2022
- Shift
- 25 Jul Shift 2
- Q Number
- Q13
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 4: Magnetic Effects of Current
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