Q70.If the binding energy of the electron in a hydrogen atom is 13.6eV, the energy required to remove the electron from the first excited state of Li++ is (1) 30.6eV (2) 13.6eV (3) 3.4eV (4) 122.4eV
What This Question Tests
This question applies the Bohr model's energy formula for hydrogenic atoms to calculate the ionization energy from the first excited state of Li++.
Concepts Tested
Formulas Used
E_n = -13.6 * (Z²/n²) eV
📚 NCERT Sections This Tests
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
📋 Question Details
- Chapter
- Atoms
- Topic
- Bohr model, Energy levels
- Year
- 2003
- Shift
- Unknown
- Q Number
- Q70
- Type
- Numerical
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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