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PhysicsMediumMCQ2021 · 20 Jul Shift 1

Q19.A nucleus of mass M emits γ -ray photon of frequency v. The loss of internal energy by the nucleus is: [Take c as the speed of electromagnetic wave] (1) hv (2) 0 (3) hv[1 − 2Mc2hv ] (4) hv[1 + 2Mc2hv ]

What This Question Tests

This question explores the conservation of momentum and energy during gamma decay, accounting for the recoil kinetic energy of the nucleus when it emits a photon, leading to a total loss of internal energy.

Concepts Tested

Gamma decayConservation of momentumConservation of energyRecoil energy of nucleus

Formulas Used

E_photon = hv

p_photon = E_photon/c

p_nucleus = p_photon

KE_nucleus = p_nucleus²/ (2M)

Loss of internal energy = E_photon + KE_nucleus

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