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MathsMediumMCQ2023 · 15 Apr Shift 1

Q80.A bag contains 6 white and 4 black balls. A die is rolled once and the number of balls equal to the number obtained on the die are drawn from the bag at random. The probability that all the balls drawn are white is (1) 1 (2) 11 4 50 (3) 1 (4) 9 5 50

What This Question Tests

This problem involves applying the total probability theorem. It requires calculating the probability of drawing a specific number of balls (determined by a die roll) and the probability that all drawn balls are white, for each possible die outcome.

Concepts Tested

Probability of eventsCombinations (selection without replacement)Total probability theorem

Formulas Used

P(E) = P(E|A1)P(A1) + P(E|A2)P(A2) + ...

Combinations C(n, k) = n! / (k!(n-k)! )

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9.17 (a) sin i¢c = 1.44/1.68 which gives i¢c = 59°. Total internal reflection takes place when i > 59° or when r < rmax = 31°. Now, (sin i /sin r max max ) = 1.68 , which gives imax ~ 60°. Thus, all incident rays of angles in the range 0 < i < 60° will suffer total internal reflections in the pipe. (If the length of the pipe is finite, which it is in practice, there will be a lower limit on i determined by the ratio of the diameter to the length of the pipe.) (b) If there is no outer coating, i¢c = sin–1(1/1.68) = 36.5°. Now, i = 90° will have r = 36.5° and i¢ = 53.5° which is greater than i¢c. Thus, all incident rays (in the range 53.5° < i < 90°) will suffer total internal reflections.

📋 Question Details

Chapter
Probability
Topic
Conditional probability and total probability
Year
2023
Shift
15 Apr Shift 1
Q Number
Q80
Type
MCQ
NCERT Ref
Class 12 Mathematics Ch 13: Probability

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