Q76.The domain of the function f(x) = 1 is √|x|−x (1) (0, ∞) (2) (−∞, 0) (3) (−∞, ∞) −{0} (4) (−∞, ∞)
What This Question Tests
This question tests the ability to determine the domain of a function involving a square root and a fraction, requiring consideration of both non-negative radicand and non-zero denominator conditions.
Concepts Tested
Formulas Used
√(f(x)) implies f(x) ≥ 0
1/f(x) implies f(x) ≠ 0
|x| = x if x ≥ 0, |x| = -x if x < 0
📚 NCERT Sections This Tests
9.15 — Apply Mirror Equation And The Condition:
Physics Class 12 · Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
14.2 — Which Of The Statements Given In Exercise 14.1 Is True For P-Type
Physics Class 12 · Chapter 14
14.2 Which of the statements given in Exercise 14.1 is true for p-type semiconductos.
📋 Question Details
- Chapter
- Sets Relations Functions
- Topic
- Domain of a function
- Year
- 2011
- Shift
- Unknown
- Q Number
- Q76
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 2: Relations and Functions
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