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PhysicsEasyMCQ2025 · 23 Jan Shift 2

Q45.In photoelectric effect an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and stopping potential is 2 V , what is the wavelength of the em- wave ? (Given hc = 1242eVnm where h is the Planck's constant and c is the speed of light in vaccum.) 2025 (23 Jan Shift 2) JEE Main Previous Year Paper (1) 300 nm (2) 400 nm (3) 600 nm (4) 200 nm

What This Question Tests

This question is a straightforward application of Einstein's photoelectric equation, relating the maximum kinetic energy of emitted electrons to work function and incident photon energy. It tests the ability to calculate the wavelength of an EM wave given stopping potential and work function.

Concepts Tested

Photoelectric equationWork functionStopping potentialWavelength of electromagnetic wave

Formulas Used

Kmax = eVs

Kmax = hν - φ

hν = hc/λ

📚 NCERT Sections This Tests

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