Q72. limx→0 ( x−sinx x ) sin ( x1 ) (1) equals 1 (2) equals 0 (3) does not exist (4) equals −1
What This Question Tests
This problem requires careful evaluation of a limit involving an oscillating term. It combines the Taylor series expansion for sin(x) with the behavior of sin(1/x) as x approaches 0, leading to a limit that does not exist.
Concepts Tested
Formulas Used
lim (x->0) sinx/x = 1
Taylor series expansion of sinx
📚 NCERT Sections This Tests
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
4.13 — How Is The Variability In Oxidation States Of Transition Metals Different From
Chemistry Class 11 · Chapter 4
4.13 How is the variability in oxidation states of transition metals different from that of the non transition metals? Illustrate with examples.
📋 Question Details
- Chapter
- Limits & Continuity
- Topic
- Evaluation of limits
- Year
- 2012
- Shift
- 07 May Online
- Q Number
- Q72
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 13: Limits and Derivatives
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