Q47.If the solubility product of AB2 is 3. 20 × 10−11 M3 , then the solubility of AB2 in pure water is _______ ×10−4 mol L−1 [Assuming that neither kind of ion reacts with water]
What This Question Tests
This question tests the understanding of the relationship between solubility product (Ksp) and molar solubility (s) for a sparingly soluble salt of AB₂ type.
Concepts Tested
Formulas Used
Ksp = 4s³
📚 NCERT Sections This Tests
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
2.8 — The Conductivity Of 0.20 M Solution Of Kcl At 298 K Is 0.0248 S Cm–1. Calculate
Chemistry Class 11 · Chapter 2
2.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.
2.7 — Define Conductivity And Molar Conductivity For The Solution Of An Electrolyte.
Chemistry Class 11 · Chapter 2
2.7 Define conductivity and molar conductivity for the solution of an electrolyte. Discuss their variation with concentration.
📋 Question Details
- Chapter
- Ionic Equilibrium
- Topic
- Solubility product (Ksp)
- Year
- 2020
- Shift
- 06 Sep Shift 2
- Q Number
- Q47
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 7: Ionic Equilibrium
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