Q62.The number of complex numbers z such that |z −1| = |z + 1| = |z −i| equals (1) 1 (2) 2 (3) ∞ (4) 0
What This Question Tests
This question tests the geometric interpretation of the modulus of a complex number, specifically finding a point equidistant from three given points, which is the circumcenter.
Concepts Tested
Formulas Used
|z| = sqrt(x^2 + y^2)
|z1 - z2| = distance between z1 and z2
📚 NCERT Sections This Tests
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5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
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5.11 Draw all the isomers (geometrical and optical) of: (i) [CoCl2(en)2] + (ii) [Co(NH3)Cl(en)2] 2+ (iii) [Co(NH3)2Cl2(en)]+
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
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2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
📋 Question Details
- Chapter
- Complex Numbers
- Topic
- Geometric interpretation of complex numbers
- Year
- 2010
- Shift
- Unknown
- Q Number
- Q62
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 5: Complex Numbers and Quadratic Equations
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