Q61.If x2 + 9y2 −4x + 3 = 0, x, y ∈R, then x and y respectively lie in the intervals (1) [−13 , 13 ] and [−13 , 13 ] (2) [1, 3] and [−13 , 13 ] (3) [−13 , 13 ] and [1, 3] (4) [1, 3] and [1, 3]
What This Question Tests
This question tests the application of the Carius method for quantitative analysis of halogens, specifically calculating the percentage of bromine in an organic compound from the mass of AgBr formed.
Concepts Tested
Formulas Used
% of Br = (mass of AgBr / Molar mass of AgBr) * (Molar mass of Br / mass of organic compound) * 100
📚 NCERT Sections This Tests
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
9.4 — Alkynes 1 2 3 4 5
Chemistry Class 12 · Chapter 9
9.4 Alkynes 1 2 3 4 5 Like alkenes, alkynes are also unsaturated II. H3C–C≡ C– CH2– CH3 Pent–2-yne hydrocarbons. They contain at least one triple 4 3 2 1 bond between two carbon atoms. The number III. H3C–CH–C≡ CH 3-Methyl but–1-yne |of hydrogen atoms is still less in alkynes as CH3compared to alkenes or alkanes. Their general Structures I and II are position isomers formula is CnH2n–2. and structures I and III or II and III are chain The first stable member of alkyne series isomers. is ethyne which is popularly known as acetylene. Acetylene is used for arc welding Problem 9.13 purposes in the form of oxyacetylene flame Write structures of different isomers obtained by mixing acetylene with oxygen corresponding to the 5 th member of gas. Alkynes are starting materials for a large alkyne series. Also write IUPAC names of number of organic compounds. Hence, it all the isomers. What type of isomerism is interesting to study this class of organic is exhibited by different pairs of isomers? compounds. Solution 9.4.1 Nomenclature and Isomerism th 5 member of alkyne has the molecular In common system, alkynes are named as formula C6H10. The possible isomers are: derivatives of acetylene. In IUPAC system, they Table 9.2 Common and IUPAC Names of Alkynes (CnH2n–2) Value of n Formula Structure Common name IUPAC name 2 C2H2 H-C≡CH Acetylene Ethyne 3 C3H4 CH3-C≡CH Methylacetylene Propyne 4 C4H6 CH3CH2-C≡CH Ethylacetylene But-1-yne 4 C4H6 CH3-C≡C-CH3 Dimethylacetylene But-2-yne Reprint 2025-26 Hydrocarbons 315 (a) HC ≡ C – CH2 – CH2 – CH2 – CH3 Hex-1-yne (b) CH3 – C ≡ C – CH2 – CH2 – CH3 Hex-2-yne (c) CH3 – CH2 – C ≡ C – CH2– CH3 Hex-3-yne 3-Methylpent-1-yne 4-Methylpent-1-yne 4-Methylpent-2-yne Fig. 9.6 Orbital picture of ethyne showing (a) sigma overlaps (b) pi overlaps. orbitals of the other carbon atom, which undergo lateral or sideways overlapping to 3,3-Dimethylbut-1-yne form two pi (π) bonds between two carbon atoms. Thus ethyne molecule consists of one Position and chain isomerism shown by C–C σ bond, two C–H σ bonds and two C–C different pairs. π bonds. The strength of C≡C bond (bond enthalpy 823 kJ mol -1) is more than those 9.4.2 Structure of Triple Bond of C=C bond (bond enthalpy 681 kJ mol –1) Ethyne is the simplest molecule of alkyne and C–C bond (bond enthalpy 348 kJ mol–1). series. Structure of ethyne is shown in The C≡C bond length is shorter (120 pm) Fig. 9.6. than those of C=C (133 pm) and C–C (154 pm). Electron cloud between two carbon Each carbon atom of ethyne has two sp atoms is cylindrically symmetrical about thehybridised orbitals. Carbon-carbon sigma (σ) internuclear axis. Thus, ethyne is a linear bond is obtained by the head-on overlapping molecule. of the two sp hybridised orbitals of the two carbon atoms. The remaining sp hybridised 9.4.3 Preparation orbital of each carbon atom undergoes 1. From calcium carbide: On industrial overlapping along the internuclear axis with scale, ethyne is prepared by treating the 1s orbital of each of the two hydrogen calcium carbide with water. Calcium atoms forming two C-H sigma bonds. carbide is prepared by heating quick lime H-C-C bond angle is of 180°. Each carbon with coke. Quick lime can be obtained byhas two unhybridised p orbitals which are heating limestone as shown in the followingperpendicular to each other as well as to the reactions:plane of the C-C sigma bond. The 2p orbitals of one carbon atom are parallel to the 2p CaCO3 ∆ CaO + O2 (9.55) Reprint 2025-26 316 chemistry CaO + 3C CaC2 + CO (9.56) the sp hybridised carbon2 atoms whereas they are attached to sp hybridised carbon Calcium 3 atoms in ethene and sp hybridised carbons carbide in ethane. Due to the maximum percentage of CaC2 + 2H2O Ca(OH)2 + C2H2 (9.57) s character (50%), the sp hybridised orbitals of carbon atoms in ethyne molecules have2. From vicinal dihalides : Vicinal dihalides highest electronegativity; hence, these attract on treatment with alcoholic potassium the shared electron pair of the C-H bond of hydroxide undergo dehydrohalogenation. ethyne to a greater extent than that of the One molecule of hydrogen halide is 2 sp hybridised orbitals of carbon in ethene eliminated to form alkenyl halide which 3 and the sp hybridised orbital of carbon in on treatment with sodamide gives alkyne. ethane. Thus in ethyne, hydrogen atoms can be liberated as protons more easily as compared to ethene and ethane. Hence, hydrogen atoms of ethyne attached to triply bonded carbon atom are acidic in nature. You may note that the hydrogen atoms attached to the triply bonded carbons are acidic but not all the hydrogen atoms of alkynes. HC ≡ CH + Na → HC ≡ C–Na++ 1/2 H2 9.4.4 Properties Monosodium Physical properties ethynide Physical properties of alkynes follow the same (9.59) trend of alkenes and alkanes. First three HC ≡ C– Na + Na → Na+ C–Na+ ≡ C–Na++ 1/2 H2members are gases, the next eight are liquids and the higher ones are solids. All alkynes Disodium ethynide are colourless. Ethyene has characteristic (9.60)odour. Other members are odourless. Alkynes are weakly polar in nature. They are lighter CH3 – C ≡ C – H + Na+ NH–2 than water and immiscible with water but ↓ soluble in organic solvents like ethers, carbon CH3 – C ≡ C– Na+ + NH3 tetrachloride and benzene. Their melting Sodium propynide (9.61) point, boiling point and density increase with These reactions are not shown by alkenesincrease in molar mass. and alkanes, hence used for distinction Chemical properties between alkynes, alkenes and alkanes. What Alkynes show acidic nature, addition reactions about the above reactions with but-1-yne and and polymerisation reactions as follows : but-2-yne ? Alkanes, alkenes and alkynes A. Acidic character of alkyne: Sodium follow the following trend in their acidic metal and sodamide (NaNH2) are strong behaviour : bases. They react with ethyne to form sodium i) CH ≡ CH > H2C – CH2 > CH3 –CH3acetylide with the liberation of dihydrogen gas. These reactions have not been observed ii) HC ≡ CH > CH3 –C≡ CH >> CH3 –C≡C–CH3in case of ethene and ethane thus indicating that ethyne is acidic in nature in comparison B. Addition reactions: Alkynes contain a to ethene and ethane. Why is it so ? Has triple bond, so they add up, two molecules of it something to do with their structures dihydrogen, halogen, hydrogen halides etc. and the hybridisation ? You have read that Formation of the addition product takes place hydrogen atoms in ethyne are attached to according to the following steps. Reprint 2025-26 Hydrocarbons 317 The addition product formed depends upon stability of vinylic cation. Addition in unsymmetrical alkynes takes place according to Markovnikov rule. Majority of the reactions of alkynes are the examples of electrophilic addition reactions. A few addition reactions (9.66)are given below: (i) Addition of dihydrogen (iv) Addition of water Pt/Pd/Ni H2 Like alkanes and alkenes, alkynes are alsoHC≡CH+H2 [H2C = CH2] CH3–CH3 immiscible and do not react with water. (9.62) However, one molecule of water adds to alkynes on warming with mercuric sulphate CH3–C≡CH + H2 Pt/Pd/Ni [CH3–CH=CH2] and dilute sulphuric acid at 333 K to form Propyne Propene carbonyl compounds. ↓H2 CH3–CH2–CH3 Propane (9.63) (ii) Addition of halogens (9.67) (9.64) Reddish orange colour of the solution of bromine in carbon tetrachloride is decolourised. This is used as a test for unsaturation. (iii) Addition of hydrogen halides (9.68) Two molecules of hydrogen halides (HCl, HBr, (v) Polymerisation HI) add to alkynes to form gem dihalides (in (a) Linear polymerisation: Under suitable which two halogens are attached to the same conditions, linear polymerisation of ethyne carbon atom) takes place to produce polyacetylene or H–C≡C–H+H–Br [CH2 = CH–Br]→ CHBr2 polyethyne which is a high molecular Bromoethene weight polyene containing repeating units of CH3 (CH = CH – CH = CH ) and can be represented 1,1-Dibromoethane as —(CH = CH – CH = CH)n— Under special (9.65) conditions, this polymer conducts electricity. Reprint 2025-26 318 chemistry Thin film of polyacetylene can be used as but in a majority of reactions of aromatic electrodes in batteries. These films are good compounds, the unsaturation of benzene ring conductors, lighter and cheaper than the is retained. However, there are examples of metal conductors. aromatic hydrocarbons which do not contain a (b) Cyclic polymerisation: Ethyne on benzene ring but instead contain other highly unsaturated ring. Aromatic compoundspassing through red hot iron tube at 873K containing benzene ring are known asundergoes cyclic polymerization. Three benzenoids and those not containing amolecules polymerise to form benzene, which benzene ring are known as non-benzenoids.is the starting molecule for the preparation of Some examples of arenes are givenderivatives of benzene, dyes, drugs and large below:number of other organic compounds. This is the best route for entering from aliphatic to aromatic compounds as discussed below: Benzene Toluene Naphthalene (9.69) Biphenyl Problem 9.14 How will you convert ethanoic acid into 9.5.1 Nomenclature and Isomerism benzene? The nomenclature and isomerism of aromatic Solution hydrocarbons has already been discussed in Unit 8. All six hydrogen atoms in benzene are equivalent; so it forms one and only one type of monosubstituted product. When two hydrogen atoms in benzene are replaced by two similar or different monovalent atoms or groups, three different position isomers are possible. The 1, 2 or 1, 6 is known as the ortho (o–), the 1, 3 or 1, 5 as meta (m–) and the 1, 4 as para (p–) disubstituted compounds. A few examples of derivatives of benzene are given below:
5.23 — Give The Oxidation State, D Orbital Occupation And Coordination Number Of
Chemistry Class 11 · Chapter 5
5.23 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes: (i) K3[Co(C2O4)3] (iii) (NH4)2[CoF4] (ii) cis-[CrCl2(en)2]Cl (iv) [Mn(H2O)6]SO4
📋 Question Details
- Chapter
- Qualitative Analysis
- Topic
- Carius method for halogens
- Year
- 2021
- Shift
- 27 Aug Shift 1
- Q Number
- Q61
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 12: Organic Chemistry - Some Basic Principles and Techniques
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Total number of such numbers are (1) 312 (2) 3125 (3) 120 (4) 216 Q164.If 1, log9 (31−x + 2), log3 (4.3x −1) are in A.P. then x equals (1) log3 4 (2) 1 + log3 4 (3) 1 - log3 4 (4) log4 3 Q165.The value of 21/4, 41/8, 81/6 + … … ∞ is (1) 1 (2) 2 (3) 3/2 (4) 4 Q166.Fifth term of a GP is 2, then the product of its 9 terms is (1) 256 (2) 512 (3) 1024 (4) none of these Q167.Sum of infinite number of terms of GP is 20 and sum of their square is 100. The common ratio of GP is (1) 5 (2) 3/5 (3) 8/5 (4) 1/5 Q168. 13 −23 + 33 −43 + … . +93 = (1) 425 (2) -425 (3) 475 (4) -475 Q169.The sum of integers from 1 to 100 that are divisible by 2 or 5 is (1) 3000 (2) 3050 (3) 3600 (4) 3250 Q170.If an = √7 + √7 + √7 + … . having n radical signs then by methods of mathematical induciton which is true (1) an > 7∀n ≥1 (2) an > 7∀n ≥1 (3) an < 4∀n ≥1 (4) an < 3∀n ≥1 Q171.The coefficients of xp and xq in the expansion of (1 + x)p+q are (1) equal (2) equal with opposite signs (3) reciprocals of each other (4) none of these Q172.If the sum of the coefficients in the expansion of (a + b)n is 4096 , then the greatest coefficient in the expansion is (1) 1594 (2) 792 (3) 924 (4) 2924 Q173.The positive integer just greater than (1 + 0.0001)10000 is JEE Main 2002 JEE Main Previous Year Paper (1) 4 (2) 5 (3) 2 (4) 3 Q174. r and n are positive integers r > 1, n > 2 and coefficient of (r + 2)th term and 3rth term in the expansion of (1 + x)2n are equal, then n equals (1) 3r (2) 3r + 1 (3) 2r (4) 2r + 1 Q175.The period of sin2 θ is (1) π2 (2) π (3) 2π (4) π/2 Q176.The number of solution of tan x + sec x = 2 cos x in [0, 2π) is (1) 2 (2) 3 (3) 0 (4) 1 Q177.A triangle with vertices (4, 0), (-1, -1), (3, 5) is (1) isosceles and right angled (2) isosceles but not right angled (3) right angled but not isosceles (4) neither right angled nor isoceles Q178.The sides of a triangle are 3x + 4y, 4x+37 and 5x + 57 where x, y > 0 then the triangle is (1) right angled (2) obtuse angled (3) equilateral (4) none of these Q179.If the pair of lines ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 intersect on the y - axis then (1) 2fgh = bg2 + ch2 (2) bg2 ≠ch2 (3) abc = 2fgh (4) none of these Q180.The point of lines represented by 3ax2 + 5xy + (a2 −2)y2 = 0 and perpendicular to each other for (1) two values of a (2) ∀a (3) for one value of a (4) for no values of a Q181.Locus of mid point of the portion between the axes of x cos α + y sin α = p where p is constant is (1) x2 + y2 = 4 (2) x2 + y2 = 4p2 p2 (3) 1 + 1 = 2 (4) 1 + 1 = 4 x2 y2 p2 x2 y2 p2 Q182.If the chord y = mx + 1 of the circle x2 + y2 = 1 subtends an angle of measure 450 at the major segment of the circle then value of m is (1) 2 ± √2 (2) −2 ± √2 (3) −1 ± √2 (4) none of these Q183.The centres of a set of circles, each of radius 3 , lie on the circle x2 + y2 = 25. The locus of any point in the set is (1) 4 ≤x2 + y2 ≤64 (2) x2 + y2 ≤25 (3) x2 + y2 ≥25 (4) 3 ≤x2 + y2 ≤9 Q184.The centre of the circle passing through (0, 0) and (1, 0) and touching the circle x2 + y2 = 9 is JEE Main 2002 JEE Main Previous Year Paper , −√2) (1) ( 21 , 12 ) (2) ( 12 (3) ( 23 , 12 ) (4) ( 12 , 32 ) Q185.Two common tangents to the circle x2 + y2 = 2a2 and parabola y2 = 8ax are (1) x = ±(y + 2a) (2) y = ±(x + 2a) (3) x = ±(y + a) (4) y = ±(x + a) Q186. (1) 1 (2) -1 (3) zero (4) does not exist Q187. (1) e4 (2) e2 (3) e3 (4) 1 Q188.Let f(x) = 4 and f ′(x) = 4. Then Limx→2 xf(2)−2f(x)x−2 is given by (1) 2 (2) -2 (3) -4 (4) 3 Q189. 1p + 2p + 3p + … + np Limn→∞ np+1 is (1) 1 (2) 1 p+1 1−p (3) p 1 − p−11 (4) p+21 denotes greatest integer less than or equal to x) Q190. Limx→0 log xn−[x][x] , n ∈N([x] (1) has value -1 (2) has value 0 (3) has value 1 (4) does not exist Q191.If f(1) = 1, f ′(1) = 2, then Limx→1 √f(x)−1 is √x−1 (1) 2 (2) 4 (3) 1 (4) 1/2 Q192.In a class of 100 students there are 70 boys whose average marks in a subject are 75. If the average marks of the complete class is 72, then what is the average of the girls? (1) 73 (2) 65 (3) 68 (4) 74 Q193.The equation of a circle with origin as a centre and passing through equilateral triangle whose median is of length 3a is JEE Main 2002 JEE Main Previous Year Paper (1) x2 + y2 = 9a2 (2) x2 + y2 = 16a2 (3) x2 + y2 = 4a2 (4) x2 + y2 = a2 Q194.In a triangle with sides a, b, c, r1 > r2 > r3 (which are the ex-radii) then (1) a > b > c (2) a < b < c (3) a > b and b < c (4) a < b and b > c Q195. log l p 1 l, m, n are the pth , qth and rth term of a G.P. all positive, then log m q 1 equals log n r 1 (1) -1 (2) 2 (3) 1 (4) 0 Q196. a b ax + b If a > 0 discriminant of ax2 + 2bx + c is -ve, then b c bx + c is ax + b bx + c 0 (1) +ve (2) (ac −b2) (ax2 + 2bx + c) (3) -ve (4) 0 Q197. cot−1(√cos α) = tan−1(√cos α) = x, then sin x = (1) tan2 ( α2 ) (2) cot2 ( α2 ) (3) tan α (4) cot ( α2 ) Q198.The domain of sin−1 [log3(x/3)] is (1) [1, 9] (2) [-1,9] (3) [-9, 1] (4) [-9, -1] Q199.Which one is not periodic (1) |sin 3x| + sin2 x (2) cos √x + cos2 x (3) cos 4x + tan2 x (4) cos 2x + sin x Q200.If f(x + y) = f(x) ⋅f(y)∀x ⋅y and f(5) = 2, f ′(0) = 3 then f ′(5) is (1) 0 (2) 1 (3) 6 (4) 2 Q201.f is defined in [-5, 5] as f(x) = x if x is rational and = -x is irrational. Then (1) f(x) is continuous at every x, except x = 0 (2) f(x) is discontinuous at every x, except x = 0 (3) f(x) is continuous everywhere (4) f(x) is discontinuous everywhere n d2y dy (1 + x2) dx2 + x dx is Q202.If y = (x + √1 + x2) , then (1) n2y (2) −n2y (3) −y (4) 2x2y Q203.The maximum distance from origin of a point on the curve x = a sin t −b sin ( atb ) y = a cos t −b cos ( atb ), both a, b > 0 is (1) a - b (2) a + b (3) √a2 + b2 (4) √a2 −b2 JEE Main 2002 JEE Main Previous Year Paper Q204. ∫10π0 | sin x|dx is (1) 20 (2) 8 (3) 10 (4) 18 xdx then Limn→∞n [In + In−2] equals Q205. In = ∫π/40 tann (1) 1/2 (2) 1 (3) ∞ (4) zero is Q206. ∫ 0√2 [x2]dx (1) 2 −√2 (2) 2 + √2 (3) √2 −1 (4) √2 −2 Q207. ∫π−π 2x(1+sin1+cos2 xx) dx is (1) π2 (2) π2 4 (3) zero (4) π 2 Q208.If y = f(x) makes +ve intercept of 2 and 0 unit on x and y axes and encloses an area of 3/4 square unit with the axes then ∫20 xf ′(x)dx is (1) 3/2 (2) 1 (3) 5/4 (4) -3/4 Q209.The area bounded by the curves y = ln x, y = ln |x|, y = | ln x| and y = | ln ||x| is (1) 4 sq. units (2) 6 sq. units (3) 10 sq. units (4) none of these d3y Q210.The order and degree of the differential equation 2/3 are + 3 dx = 4 dx3 (1 dy ) (1) (1, 32 ) (2) (3, 1) (3) (3, 3) (4) (1, 2) Q211.The solution of the equation d2y = e−2x dx2 (1) e−2x (2) e−2x 4 4 + cx + d (3) 4 1 e−2x + cx2 + d (4) 14 e−4x + cx + d Q212. f(x) and g(x) are two differentiable functions on [0, 2] such that f ′′(x) −g′′(x) = 0 f ′(1) = 2g′(1) = 4f(2) = 3g(2) = 9 then f(x) −g(x) at x = 3/2 is (1) 0 (2) 2 (3) 10 (4) 5 Q213.If |→a| = 4, |→b| = 2 and the angle between →a and →b is π/6 then (→a × →b)2 = 2 is equal to (1) 48 (2) 16 (3) →a (4) none of these Q214. If →a,→b, →c are vectors such that |→a→b→c| = 4 then (1) 16 (2) 64 (3) 4 (4) 8 JEE Main 2002 JEE Main Previous Year Paper Q215.If →a,→b, →c are vectors such that →a + →b + →c = 0 and |→a| = 7, |→b| = 5, |→c| = 3 then angle between vector →b and →c is (1) 60∘ (2) 30∘ (3) 45∘ (4) 90∘ Q216.If |a| = 5, |b| = 4, |c| = 3 thus what will be the value of |a ⋅b + b. c + c. a| , given that →a + →b + →c = 0 (1) 25 (2) 50 (3) -25 (4) -50 Q217. 3λ→c + 2μ(→a × →b) = 0 then (1) 3λ + 2μ = 0 (2) 3λ = 2μ (3) λ = μ (4) λ + μ = 0 Q218. →a = 3^i −5^j and →b = 6^i + 3^j are two vectors and →c is a vector such that →c = →a × →b then |→a| : |→b| : |→c| (1) √34 : √45 : √39 (2) √34 : √45 : 39 (3) 34 : 39 : 45 (4) 39 : 35 : 34 Q219.If →a × →b = →b × →c = →c × →a then →a + →b + →c = (1) abc (2) -1 (3) 0 (4) 2 Q220.The sum of two forces is 18 N and resultant whose direction is at right angles to the smaller force is 12 N. The magnitude of the two forces are (1) 13, 5 (2) 12, 6 (3) 14, 4 (4) 11, 7 Q221.A plane which passes through the point (3, 2, 0) and the line x−41 = y−75 = z−44 is (1) x - y + z = 1 (2) x + y + z = 5 (3) x + 2y - z = 1 (4) 2x - y + z = 5 Q222.The d.r. of normal to the plane through (1, 0, 0), (0, 1, 0) which makes an angle π/4 with plane x + y = 3 are (1) 1, √2, 1 (2) 1, 1, √2 (3) 1, 1, 2 (4) √2, 1, 1 Q223.A problem in mathematics is given to three students A, B, C and their respective probability of solving the problem is 2 1 , 13 and 14 . Probability that the problem is solved is (1) 3 (2) 1 4 2 (3) 2 (4) 1 3 3 Q224. A and B are events such that P(A ∪B) = 3/4, P(A ∩B) = 1/4, P(¯A) = 2/3 then P(¯A ∩B) is (1) 5/12 (2) 3/8 (3) 5/8 (4) 1/4 Q225.A die is tossed 5 times. Getting an odd number is considered a success. Then the variance of distribution of success is JEE Main 2002 JEE Main Previous Year Paper (1) 8/3 (2) 3/8 (3) 4/5 (4) 5/4 JEE Main 2002 JEE Main Previous Year Paper
Q40.The correct order of increasing basicity of the given conjugate bases (R = CH3) is –––––– (1) RCOO < HC = C < R < NH2 (2) R < HC ≡C < RCOO < NH2 ––––– (3) RCOO < NH2 < HC ≡C < R (4) RCOO < HC ≡C < NH2 < R
Q43.Copper wire test for halogens is known as (1) Duma's Test (2) Beilstein's Test (3) Liebig's Test (4) Lassigne's Test
Q45.Beilstein test is used for the estimation of which one of the following elements? (1) S (2) Cl (3) C and H (4) N