Q23.A liquid column of height 0.04 cm balances excess pressure of a soap bubble of certain radius. If density of liquid is 8 × 103 kg m−3 and surface tension of soap solution is 0.28Nm−1 , then diameter of the soap bubble is _____ cm . (if g = 10 m s−2 )
What This Question Tests
This question tests the understanding of excess pressure inside a soap bubble due to surface tension and how it can be balanced by the pressure of a liquid column. It requires equating the two pressure formulas and solving for the diameter.
Concepts Tested
Formulas Used
ΔP_bubble = 4T/R
ΔP_liquid = ρgh
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1.36 100 g of liquid A (molar mass 140 g mol–1) was dissolved in 1000 g of liquid B (molar mass 180 g mol–1). The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr. 29 Solutions Reprint 2025-26
📋 Question Details
- Chapter
- Properties of Matter
- Topic
- Surface Tension - Soap Bubble
- Year
- 2024
- Shift
- 08 Apr Shift 1
- Q Number
- Q23
- Type
- Numerical
- NCERT Ref
- Class 11 Physics Ch 10: Mechanical Properties of Fluids
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