Q57.Phenol on treatment with CO2 in the presence of NaOH followed by acidification produces compound X as the major product. X on treatment with (CH3CO)2 O in the presence of catalytic amount of H2SO4 produces: JEE Main 2018 (08 Apr) JEE Main Previous Year Paper (1) (2) (3) (4)
What This Question Tests
This question involves a two-step synthesis starting with phenol undergoing Kolbe's reaction to form salicylic acid, followed by acetylation of the phenolic hydroxyl group with acetic anhydride to form Aspirin.
Concepts Tested
📚 NCERT Sections This Tests
7.17 — Give Equations Of The Following Reactions:
Chemistry Class 12 · Chapter 7
7.17 Give equations of the following reactions: (i) Oxidation of propan-1-ol with alkaline KMnO4 solution. (ii) Bromine in CS2 with phenol. (iii) Dilute HNO3 with phenol. (iv) Treating phenol wih chloroform in presence of aqueous NaOH.
7.14 — Give Two Reactions That Show The Acidic Nature Of Phenol. Compare Acidity
Chemistry Class 12 · Chapter 7
7.14 Give two reactions that show the acidic nature of phenol. Compare acidity of phenol with that of ethanol.
7.7 — Predict The Major Product Of Acid Catalysed Dehydration Of
Chemistry Class 12 · Chapter 7
7.7 Predict the major product of acid catalysed dehydration of (i) 1-methylcyclohexanol and (ii) butan-1-ol
📋 Question Details
- Chapter
- Alcohols Phenols Ethers
- Topic
- Reactions of phenols
- Year
- 2018
- Shift
- 08 Apr
- Q Number
- Q57
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 11: Alcohols, Phenols and Ethers; Class 12 Chemistry Ch 12: Aldehydes, Ketones and Carboxylic Acids
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Q56.The major product obtained on interaction of phenol with sodium hydroxide and carbon dioxide is : (1) benzoic acid (2) salicylaldehyde (3) salicylic acid (4) phthalic acid
Q43.The edge length of a face centered cubic cell of an ionic substance is 508pm. If the radius of the cation is 110pm, the radius of the anion is (1) 288pm (2) 398pm (3) 618pm (4) 144pm