Q51.Electromagnetic radiation of wavelength 663 nm is just sufficient to ionise the atom of metal A . The ionization energy of metal A in kJ mol−1 is ___. (Rounded-off to the nearest integer) [h = 6. 63 × 10−34 Js, c = 3. 00 × 108 ms−1, NA = 6. 02 × 1023 mol−1]
What This Question Tests
This question requires calculating the ionization energy of a metal atom using the given wavelength of electromagnetic radiation and fundamental constants, then converting it to kJ/mol.
Concepts Tested
Formulas Used
E = hc/λ
Ionization Energy (kJ/mol) = E (J/atom) × NA / 1000
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
11.6 — The Threshold Frequency For A Certain Metal Is 3.3 × 1014 Hz. If Light
Physics Class 12 · Chapter 11
11.6 The threshold frequency for a certain metal is 3.3 × 1014 Hz. If light of frequency 8.2 × 1014 Hz is incident on the metal, predict the cut- off voltage for the photoelectric emission.
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Photoelectric effect
- Year
- 2021
- Shift
- 25 Feb Shift 2
- Q Number
- Q51
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 2: Structure of Atom
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