RankLab
Back to Questions
ChemistryMediumMCQ2013 · 25 Apr Online

Q34.Given (A) n = 5, mℓ= +1 (B) n = 2, ℓ= 1, mℓ= −1, ms = −l/2 The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) are respectively: (1) 25 and 1 (2) 8 and 1 (3) 2 and 4 (4) 4 and 1

What This Question Tests

This question evaluates the understanding of quantum numbers and their allowed values to determine the maximum number of electrons that can possess a given set of quantum numbers, considering Pauli's exclusion principle.

Concepts Tested

Principal quantum number (n)Azimuthal quantum number (l)Magnetic quantum number (ml)Spin quantum number (ms)Pauli's exclusion principle

Formulas Used

Number of orbitals for a given n = n²

Number of orbitals for a given l = 2l+1

Maximum electrons in an orbital = 2

📚 NCERT Sections This Tests

12.5A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,

Physics Class 12 · Chapter 12

78% match

12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.

12.7The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is

Physics Class 12 · Chapter 12

77% match

12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?

12.6(A) Using The Bohr’S Model Calculate The Speed Of The Electron In A

Physics Class 12 · Chapter 12

77% match

12.6 (a) Using the Bohr’s model calculate the speed of the electron in a hydrogen atom in the n = 1, 2, and 3 levels. (b) Calculate the orbital period in each of these levels.