Q53.The difference between bond orders of CO and NO⊕ is x2 where x = (Round off to the Nearest Integer)
What This Question Tests
This question requires the application of Molecular Orbital Theory to calculate bond orders for CO and NO⁺ and then find the difference between them, testing conceptual understanding and calculation skills.
Concepts Tested
Formulas Used
Bond order = (Nb - Na) / 2
📚 NCERT Sections This Tests
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.18 — What Is Crystal Field Splitting Energy? How Does The Magnitude Of Do Decide
Chemistry Class 11 · Chapter 5
5.18 What is crystal field splitting energy? How does the magnitude of Do decide the actual configuration of d orbitals in a coordination entity?
📋 Question Details
- Chapter
- Chemical Bonding
- Topic
- Bond order
- Year
- 2021
- Shift
- 27 Jul Shift 1
- Q Number
- Q53
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 4: Chemical Bonding and Molecular Structure
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