RankLab
Back to Questions
MathsEasyMCQ2019 · 10 Apr Shift 2

Q90.Minimum number of times a fair coin must be tossed so that the probability of getting at least one head is more than 99% is: (1) 8 (2) 6 (3) 5 (4) 7 JEE Main 2019 (10 Apr Shift 2) JEE Main Previous Year Paper

What This Question Tests

This question tests the concept of complementary probability for 'at least one head' in a series of coin tosses and solving an inequality for the minimum number of trials.

Concepts Tested

Probability of 'at least one' eventComplementary probabilityBinomial probability

Formulas Used

P(at least one head) = 1 - P(no heads)

P(getting tail in one toss) = 1/2

📚 NCERT Sections This Tests

3.18For A First Order Reaction, Show That Time Required For 99% Completion

Chemistry Class 11 · Chapter 3

69% match

3.18 For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.

12.5A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,

Physics Class 12 · Chapter 12

68% match

12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.

11.7The Work Function For A Certain Metal Is 4.2 Ev. Will This Metal Give

Physics Class 12 · Chapter 11

68% match

11.7 The work function for a certain metal is 4.2 eV. Will this metal give hotoelectric emission for incident radiation of wavelength 330 nm?

📋 Question Details

Chapter
Probability
Topic
Probability of events in Bernoulli trials
Year
2019
Shift
10 Apr Shift 2
Q Number
Q90
Type
MCQ
NCERT Ref
Class 12 Mathematics Ch 13: Probability

More from this Chapter

Q90.One ticket is selected at random from 50 tickets numbered 00, 01, 02, … , 49. Then the probability that the sum of the digits on the selected ticket is 8 , given that the product of these digits is zero, equals (1) 1 (2) 1 14 7 (3) 5 (4) 1 14 50 JEE Main 2009 JEE Main Previous Year Paper

2009
Medium

Q89.Four numbers are chosen at random (without replacement) from the set {1, 2, 3, … . , 20} . Statement-1: The probability that the chosen numbers when arranged in some order will form an AP is 1 . Statement-2: If the 85 four chosen numbers from an AP, then the set of all possible values of common difference is {±1, ±2, ±3, ±4, ±5}. (1) Statement-1 is true, Statement-2 is true; (2) Statement-1 is true, Statement-2 is false Statement-2 is not the correct explanation for Statement-1 (3) Statement-1 is false, Statement-2 is true (4) Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation for Statement-1

2010
Hard

Q90.An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colour is (1) 2 (2) 1 7 21 (3) 2 (4) 1 23 3 JEE Main 2010 JEE Main Previous Year Paper

2010
Medium

Q89.Consider 5 independent Bernoulli's trials each with probability of success p . If the probability of at least one failure is greater than or equal to 31 , then p lies in the interval 32 (1) ( 34 , 1112 ] (2) [0, 12 ] (3) ( 1112 , 1] (4) ( 12 , 34 ]

2011
Medium
More Mathematics questions