Q19.In the experiment of calibration of voltmeter, a standard cell of e.m.f. 1.1 volt is balanced against 440 cm of potential wire. The potential difference across the ends of resistance is found to balance against 220 cm of the wire. The corresponding reading of voltmeter is 0.5 volt. The error in the reading of volmeter will be: (1) −0.15 volt (2) 0.15 volt (3) 0.5 volt (4) −0.05 volt
What This Question Tests
This problem tests the application of the potentiometer principle to determine the true potential difference across a resistance and subsequently calculate the error in a voltmeter's reading.
Concepts Tested
Formulas Used
V₁/L₁ = V₂/L₂
Error = V_measured - V_true
📚 NCERT Sections This Tests
3.2 — A Battery Of Emf 10 V And Internal Resistance 3 Ω Is Connected To A
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3.2 A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?
4.10 — Two Moving Coil Meters, M1 And M2 Have The Following Particulars:
Physics Class 11 · Chapter 4
4.10 Two moving coil meters, M1 and M2 have the following particulars: R1 = 10 Ω, N1 = 30, A1 = 3.6 × 10–3 m2, B1 = 0.25 T R2 = 14 Ω, N2 = 42, A2 = 1.8 × 10–3 m2, B2 = 0.50 T (The spring constants are identical for the two meters). Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M2 and M1.
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
📋 Question Details
- Chapter
- Current Electricity
- Topic
- Potentiometer
- Year
- 2014
- Shift
- 12 Apr Online
- Q Number
- Q19
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 3: Current Electricity
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