Q44.The threshold frequency for a metallic surface corresponds to an energy of 6.2eV , and the stopping potential for a radiation incident on this surface 5 V . The incident radiation lies in JEE Main 2006 JEE Main Previous Year Paper (1) X-ray region (2) ultra-violet region (3) infra-red region (4) visible region
What This Question Tests
This question requires applying Einstein's photoelectric equation to calculate the incident photon energy and then identify its corresponding region in the electromagnetic spectrum.
Concepts Tested
Formulas Used
E_k_max = eV_s
E_k_max = hν - Φ₀
E = hν
📚 NCERT Sections This Tests
11.8 — Light Of Frequency 7.21 × 1014 Hz Is Incident On A Metal Surface.
Physics Class 12 · Chapter 11
11.8 Light of frequency 7.21 × 1014 Hz is incident on a metal surface. Electrons with a maximum speed of 6.0 × 105 m/s are ejected from the surface. What is the threshold frequency for photoemission of electrons?
11.6 — The Threshold Frequency For A Certain Metal Is 3.3 × 1014 Hz. If Light
Physics Class 12 · Chapter 11
11.6 The threshold frequency for a certain metal is 3.3 × 1014 Hz. If light of frequency 8.2 × 1014 Hz is incident on the metal, predict the cut- off voltage for the photoelectric emission.
11.2 — The Work Function Of Caesium Metal Is 2.14 Ev. When Light Of
Physics Class 12 · Chapter 11
11.2 The work function of caesium metal is 2.14 eV. When light of frequency 6 ×1014Hz is incident on the metal surface, photoemission of electrons occurs. What is the (a) maximum kinetic energy of the emitted electrons, (b) Stopping potential, and (c) maximum speed of the emitted photoelectrons?
📋 Question Details
- Chapter
- Dual Nature of Matter
- Topic
- Photoelectric effect
- Year
- 2006
- Shift
- Unknown
- Q Number
- Q44
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 11: Dual Nature of Matter
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