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PhysicsMediumMCQ2025 · 29 Jan Shift 1

Q34.Consider a long straight wire of a circular cross-section (radius a) carrying a steady current I. The current is uniformly distributed across this cross-section. The distances from the centre of the wire's cross-section at which the magnetic field [inside the wire, outside the wire] is half of the maximum possible magnetic field, any where due to the wire, will be (1) [a/4, 3a/2] (2) [a/4, 2a] (3) [a/2, 2a] (4) [a/2, 3a]

What This Question Tests

The question tests the ability to calculate and compare magnetic field strengths both inside and outside a current-carrying cylindrical wire, requiring the application of Ampere's circuital law.

Concepts Tested

Magnetic field inside a current-carrying wireMagnetic field outside a current-carrying wireAmpere's circuital law

Formulas Used

B_in = (μ₀Ir) / (2πa²)

B_out = (μ₀I) / (2πr)

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