Q30.If enthalpy of atomization for Br2(l) is x kJ/mol and bond enthalpy for Br2 is y kJ/mol, the relation between them (1) is x = y. (2) does not exist. (3) is x > y. (4) is x < y.
What This Question Tests
This question differentiates between enthalpy of atomization and bond enthalpy, specifically for a liquid diatomic element, requiring consideration of the energy required for vaporization.
Concepts Tested
π NCERT Sections This Tests
3.23 β The Rate Constant For The Decomposition Of Hydrocarbons Is 2.418 Γ 10β5Sβ1
Chemistry Class 11 Β· Chapter 3
3.23 The rate constant for the decomposition of hydrocarbons is 2.418 Γ 10β5sβ1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.
12.4 β The Ground State Energy Of Hydrogen Atom Is β13.6 Ev. What Are The
Physics Class 12 Β· Chapter 12
12.4 The ground state energy of hydrogen atom is β13.6 eV. What are the kinetic and potential energies of the electron in this state?
4.11 β Explain Giving Reasons:
Chemistry Class 11 Β· Chapter 4
4.11 Explain giving reasons: (i) Transition metals and many of their compounds show paramagnetic behaviour. (ii) The enthalpies of atomisation of the transition metals are high. (iii) The transition metals generally form coloured compounds. (iv) Transition metals and their many compounds act as good catalyst.
π Question Details
- Chapter
- Thermodynamics & Thermochemistry
- Topic
- Enthalpy of atomization and bond enthalpy
- Year
- 2020
- Shift
- 09 Jan Shift 1
- Q Number
- Q30
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 6: Thermodynamics
More from this Chapter
Q89.A heat engine absorbs heat Q1 at temperature T1 and heat Q2 at temperature T2 . Work done by the engine is J (Q1 + Q2). This data (1) violates 1st law of thermodynamics (2) violates 1st law of thermodynamics if Q1 is βve (3) violates 1st law of thermodynamics if Q2 is β ve(4) does not violate 1st law of thermodynamics
Q93.If at 298 K the bond energies of C βH, C βC, C = C and H βH bonds are respectively 414, 347, 615 and 435 kJ molβ1 , the value of enthalpy change for the reaction H2C = CH2( g) + H2( g) βH3C βCH3( g) at 298 K will be (1) β250 kJ (2) +125 kJ (3) β125 kJ (4) +250 kJ
Q94.In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria (1) (dS)V,E > 0, (dG)T,P < 0 (2) (dS)V:E = 0, (dG)TPP = 0 (3) (dS)V,E = 0, (dG)T,P > 0 (4) (dS)V,E < 0, (dG)T,P < 0
Q96.The enthalpy change for a reaction does not depend upon (1) use of different reactants for the same product (2) the nature of intermediate reaction steps (3) the differences in initial or final temperatures of (4) the physical states of reactants and products involved substances