Q7. A metallic sphere cools from 50 °C to 40 °C in 300 s. If atmospheric temperature around is 20 °C, then the sphere's temperature after the nest 5 minutes will be close to: (1) 31 °C (2) 33 °C (3) 28 °C (4) 35 °C
What This Question Tests
This question applies Newton's Law of Cooling to predict the future temperature of an object based on its initial cooling rate and ambient temperature.
Concepts Tested
Formulas Used
(T₁ - T₂) / Δt = K * ((T₁ + T₂) / 2 - T_atm)
📚 NCERT Sections This Tests
3.20 — For The Decomposition Of Azoisopropane To Hexane And Nitrogen At 543
Chemistry Class 11 · Chapter 3
3.20 For the decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data are obtained. t (sec) P(mm of Hg) 0 35.0 360 54.0 720 63.0 Calculate the rate constant.
2.4 — A Spherical Conductor Of Radius 12 Cm Has A Charge Of 1.6 × 10–7C
Physics Class 11 · Chapter 2
2.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere (c) at a point 18 cm from the centre of the sphere?
3.22 — The Rate Constant For The Decomposition Of N2O5 At Various Temperatures
Chemistry Class 11 · Chapter 3
3.22 The rate constant for the decomposition of N2O5 at various temperatures is given below: T/°C 0 20 40 60 80 105 × k/s-1 0.0787 1.70 25.7 178 2140 Draw a graph between ln k and 1/T and calculate the values of A and Ea. Predict the rate constant at 30° and 50°C.
📋 Question Details
- Chapter
- Thermodynamics & KTG
- Topic
- Newton's Law of Cooling
- Year
- 2020
- Shift
- 03 Sep Shift 2
- Q Number
- Q7
- Type
- MCQ
- NCERT Ref
- Class 11 Physics Ch 11: Thermal Properties of Matter
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