Q33.Based on the equation: 1 ΔE = −2.0 × 10−18 J ( n22 −1n21 ) the wavelength of the light that must be absorbed to excite hydrogen electron from level n = 1 to level n = 2 will be: (h = 6.625 × 10−34Js, C = 3 × 108 ms−1) (1) 1.325 × 10−7 m (2) 1.325 × 10−10 m (3) 2.650 × 10−7 m (4) 5.300 × 10−10 m
What This Question Tests
This question tests the calculation of energy absorbed during an electronic transition in a hydrogen atom and its subsequent conversion to the wavelength of light using Planck's relation.
Concepts Tested
Formulas Used
ΔE = -2.0 × 10⁻¹⁸ J (1/n₂² - 1/n₁²)
ΔE = hc/λ
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Bohr's Model, Hydrogen Spectrum
- Year
- 2014
- Shift
- 11 Apr Online
- Q Number
- Q33
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 2: Structure of Atom
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